A sequence point defines any point in a computer program's execution at which it is guaranteed that all side effects of previous evaluations will have been performed, and no side effects from subsequent evaluations have yet been performed. They are often mentioned in reference to C and C++, because they are a core concept for determining the validity and, if valid, the possible results of expressions. Adding more sequence points is sometimes necessary to make an expression defined and to ensure a single valid order of evaluation.
With C++11, usage of the term sequence point has been replaced by sequencing. There are three possibilities:[1][2][3]
The execution of unsequenced evaluations can overlap, with catastrophic undefined behavior if they share state. This situation can arise in parallel computations, causing race conditions. However, it can already arise in simple non-concurrent situations like (a = 1) + (b = a)
, where part of the assignment to a
(eg., half of the bits) may happen before b = a
, and the rest afterwards, such that after evaluation of the expression, b
may contain a meaningless intermediate state of a
.
Consider two functions f()
and g()
. In C and C++, the +
operator is not associated with a sequence point, and therefore in the expression f()+g()
it is possible that either f()
or g()
will be executed first. The comma operator introduces a sequence point, and therefore in the code f(),g()
the order of evaluation is defined: first f()
is called, and then g()
is called.
Sequence points also come into play when the same variable is modified more than once within a single expression. An often-cited example is the C expression i=i++
, which apparently both assigns i
its previous value and increments i
. The final value of i
is ambiguous, because, depending on the order of expression evaluation, the increment may occur before, after, or interleaved with the assignment. The definition of a particular language might specify one of the possible behaviors or simply say the behavior is undefined. In C and C++, evaluating such an expression yields undefined behavior.[4] Other languages, such as C#, define the precedence of the assignment and increment operator in such a way that the result of the expression i=i++
is guaranteed.
In C[5] and C++,[6] sequence points occur in the following places. (In C++, overloaded operators act like functions, and thus operators that have been overloaded introduce sequence points in the same way as function calls.)
*p++ != 0 && *q++ != 0
, all side effects of the sub-expression *p++ != 0
are completed before any attempt to access q
.a = (*p++) ? (*p++) : 0
there is a sequence point after the first *p++
, meaning it has already been incremented by the time the second instance is executed.a=b;
), return statements, the controlling expressions of if
, switch
, while
, or do
-while
statements, and all three expressions in a for
statement.f(i++) + g(j++) + h(k++)
, f
is called with a parameter of the original value of i
, but i
is incremented before entering the body of f
. Similarly, j
and k
are updated before entering g
and h
respectively. However, it is not specified in which order f()
, g()
, h()
are executed, nor in which order i
, j
, k
are incremented. If the body of f
accesses the variables j
and k
, it might find both, neither, or just one of them to have been incremented. (The function call f(a,b,c)
is not a use of the comma operator; the order of evaluation for a
, b
, and c
is unspecified.)5
in the declaration int a = 5;
.a++
in int x = a++, y = a++
.[8] (This is not an example of the comma operator.)printf("foo %n %d", &a, 42)
, there is a sequence point after the %n
is evaluated and before printing 42
.
By: Wikipedia.org
Edited: 2021-06-18 15:15:30
Source: Wikipedia.org